3[2x-(3x+1)]=x+1

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Solution for 3[2x-(3x+1)]=x+1 equation:


Simplifying
3[2x + -1(3x + 1)] = x + 1

Reorder the terms:
3[2x + -1(1 + 3x)] = x + 1
3[2x + (1 * -1 + 3x * -1)] = x + 1
3[2x + (-1 + -3x)] = x + 1

Reorder the terms:
3[-1 + 2x + -3x] = x + 1

Combine like terms: 2x + -3x = -1x
3[-1 + -1x] = x + 1
[-1 * 3 + -1x * 3] = x + 1
[-3 + -3x] = x + 1

Reorder the terms:
-3 + -3x = 1 + x

Solving
-3 + -3x = 1 + x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-1x' to each side of the equation.
-3 + -3x + -1x = 1 + x + -1x

Combine like terms: -3x + -1x = -4x
-3 + -4x = 1 + x + -1x

Combine like terms: x + -1x = 0
-3 + -4x = 1 + 0
-3 + -4x = 1

Add '3' to each side of the equation.
-3 + 3 + -4x = 1 + 3

Combine like terms: -3 + 3 = 0
0 + -4x = 1 + 3
-4x = 1 + 3

Combine like terms: 1 + 3 = 4
-4x = 4

Divide each side by '-4'.
x = -1

Simplifying
x = -1

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